Question

Surface of sodium is illuminated by a light of 6000
A wavelength. Work function of sodium is 2.6 eV.
Then minimum K.E. of emitted electrons is :
(A) O eV
(B) 1.53 eV
(C) 2.46 eV
(D) 4.14 eV​

Answer 1

Answer:

(A) 0 eV

Explanation:

Given:

wavlength of light=6000Armstrong=600nm

work function of Na = 2.6 eV

Min. kinetic energy = 0