Question

Surface tension of soap bubble is 0.04n/m then pressure inside a soap buibble of 10mm dia above atmosphere is

Answer 1

Pressure exerted by atmosphere, P= 4S/r,

where S= surface tension and r= radius = 10mm/2 = 5mm= 5×10⁻³m

Given surface tension S= 0.04 N/m

So pressure P= (4×0.04)/ (5×10⁻³)

                       = 32 Pa