surface tension of water is 73dyne/cm at 20℃ , its surface area increased by 0.10m^2 then work done is ?
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1
HEYA GM ❤
★ W = T × ∆A
WORK DONE = 73 × 0.1 × 10^-6 cm²
W = 73 × 10^-7 Joules
TQ ❤ ❤
Answered by
4
Answer:
73000 ergs is the correct answer
Explanation:
work done=surface tension×increase in surface area
=73dynecm-¹×0.1m²
=73dynecm¹×0.1×10⁴ergs
=7.3×10⁴dyne cm
=73000ergs
hope it helps please mark as brainliest answer
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