Math, asked by Ghandhi945, 3 months ago

susan has 280 ribbons more than tina, mary has 65 ribbons more than tina, susan has 135 ribbons more than the total number of ribbons marry and tina have many ribbons do the three girls have

Answers

Answered by raunakthanvir
1

Answer:

Total number of ribbons the three girls= 680 ribbons

Step-by-step explanation:

susan= (280+tina)

Mary = (65 ribbons +tina)

therefore,

SUSAN-(MARY+TINA)=135

(280+TINA)-(65+TINA+TINA)=135

280+TINA-65-TINA-TINA=135

TINA-TINA-TINA=280-135

2TINA-TINA=145

TINA=145

therefore,

susan= (280+tina)=325

Mary = (65 ribbons +tina)=210

therefore,

total number of ribbons with the three girls=325+210+145=680

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