Math, asked by subh4010, 1 year ago

Susan started her homework at 1{:}59\text { p.m.}1:59 p.m.1, colon, 59, space, p, point, m, point and finished her homework 969696 minutes later. Susan had volleyball practice at 4{:}00\text{ p.m.}4:00 p.m.4, colon, 00, space, p, point, m, point How much time did Susan have between finisng her homework and the beginning of volleyball practice? 111 hour =60=60equals, 60 minutes

Answers

Answered by shivamdalmia
52
(I think you have some typing errors in the question, but I got the thing the question is asking)
Susan started her homework at = 1:59 pm
She took time = 96 mins
Time at which she had volleyball practice = 4:00 pm
So, time between her starting of homework and starting of volleyball is given by
1:59 pm to 4:00 pm = 2 hrs and 1 mins
2 hr 1 min = 120 mins + 1 min = 121 mins
But she took 96 mins to do her homework, so
Out of 121 mins, 96 mins she took for homework
Remaining time = 121 mins - 96 mins = 25 mins
Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins

Answered by summermullins
6

Answer:

25 mins long

Step-by-step explanation: its simple just right down what i put

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