Susan, wade, and Bethany sold greeting cards to raise money for their Christian schools computer lab. they sold a total of 71 boxes. wade sold one less than twice as many Susan, and Bethany sold three times as many as Susan. how many boxes did each student sell?
Answers
Answered by
75
- they sold a total of 71 boxes. wade sold one less than twice as many Susan, and Bethany sold three times as many as Susan.
Hence,
Answered by
57
Answer:
Susan = 12 boxes
Wade = 23 boxes
Bethany = 36 boxes
Step-by-step explanation:
Given:
Total number of boxes = 71
Let the boxes sold by Susan be X
According to the question,
Boxes sold by Wade = (2X-1)
Boxes sold by Antony =3X
So, the sum of boxes of Susan, wade and Antony will be equal to 71
Substituting the values, we get:
(X+2X-1+3X)=71
(3X-1+3X)=71
(6X-1)=71
6X = 71+1
6X = 72
The boxes sold by Susan = 12
Boxes sold by Wade = (2×12)-1 = 24 - 1 = 23
Boxes sold by Bethany = (3×12) = 36 boxes
Susan sold 12 boxes, wade sold 23 boxes and Bethany sold 36 boxes
Verification
The sum of everyone's boxes should be equal to
71,
12 + 23 + 36 = 71
= 35 + 36 = 71
= 71 = 71
Hence verified
Similar questions