Question

Susana gets 36% of the marks required to pass Mathematics exam. If the pass marks are 55%, then what
percentage has Susana secured in the exam?​

Answer 1

Answer:

19.8%

Step-by-step explanation:

This question is common in Tech Mahindra

Answer 2

The answer to this question is 19.8%.

Given:

Susana got 36% of the pass percentage.

Pass marks are 55%.

To Find:

We need to find what percentage Susana secured.

Solution:

Let us assume that the total marks are 'x'.

Pass marks are 55% which means

$pass \: marks = \frac{55}{100} \times x$

Susana secured 36% of these pass marks which means

$= 36\% \times ( \frac{55}{100} \times \: x)$

$= \frac{36}{100} \times \frac{55}{100} \times x$

$= \frac{1980}{10000} \times x$

$= 0.198 \times x$

These are the secured marks by Susana.

To find the percentage,

$= \frac{secured \: marks}{ total \: marks} \times 100$

$= \frac{0.198x}{x} \times 100$

$= 0.198 \times 100$

$= 19.8\%$

Therefore, the percentage of marks secured by Susana is 19.8%.

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