Question

Sushant has a vessel of the form of an inverted cone, open at the top of ht 11cm and radius of top 2.5cm ans is full of water.Metallic spherical balls each of diameter 0.5cm are put in the vessel due to which the water in the vessel flows out. Sushant made the arrangement so that the water that flows out irrigate the flower beds. What value has been shown by shusant?


Plzz ans this question..
As soon as possible bcz frm 7 march my exam was started...

Answer 1

Given that height (h) of the conical vessel = 11 cm

Radius (r1) of the conical vessel = 2.5 cm

Radius (r2) of the metallic spherical balls = 0.52 = 0.25 cm

Assume the number of spherical balls that were dropped in the vessel as 'n'.

Volume of the water spilled out of the vessel = Total volume of the spherical balls dropped

25 × Volume of the cone = n × Volume of each spherical ball

⇒25 × 1/3 πr12h = n × 4/3 πr23

⇒r12h = n × 10r23

⇒ (2.5)2 × 11 = n × 10 × (0.25)3

⇒ 68.75 = 0.15625 n

⇒ n = 440.

∴The number of spherical balls that were dropped in the vessel is 440.

Sushant made the arrangement so that the water that flows out, irrigates the flower beds.

This shows the importance of conservation of water.

Answer 2

Hope it helps you

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