Question

sushant is three years older than his brother sudesh. six years ago submachine age was four times the age of sudesh find their present ages. ​

Answer 1

Answer:
Age of sushant = 10
Age of sudesh = 7

Step-by-step explanation:

let the present age of sushant's brother be 'x'

and assume his age be (3+x)

their ages after six years ago :

subhash = (3+x) - 6
his brother = x - 6

so,

...ACCORDING TO THE QUESTION...

⇒ (3+x)-6 = (x -6)4

⇒ x - 3 = 4x - 24

⇒ x - 4x = -24 + 3

⇒ -3x = -21

⇒ x = -21/ -3

⇒ x = 7

_________________________

so, the age of sushant's brother is 7.

and age of sushant is 7 + 3 = 10 .

Answer 2

Answer

Sushant is 10 years old and Sudesh is 7 years old .

Step-by-step explanation

Sushant is three years old than his brother Sudesh .

Let the age of his brother be x .

Then the age of Sushant is x + 3 since he is 3 years older .

Six years ago , the age of Sushant was 4 times the age of Sudesh .

Six years ago , the age of Sudesh was x - 6 .

Six years ago , the age of Sushant was x + 3 - 6 = x - 3

Hence we are given that :

x - 3 = 4 ( x - 6 )

⇒ x - 3 = 4 x - 24

⇒ x - 4 x = - 24 + 3

⇒ - 3 x = - 21

⇒ x = (- 21 )/( - 3 )

⇒ x = 7

Hence we get that the present age of Sudesh is 7 years .

Then the present age of Sushant is 7 + 3 = 10 years .