Question

Sushant rides his bicycle at the speed of 2 km per hour he reaches his School late by 1 minute on increasing the speed by 2 kilometre per hour he reaches 5 minutes early find the distance between His school and his house​

Answer 1

Answer:

At speed for 2km/hr he is late by 1 min

after increasing his speed by 2km/hr his speed

is 4km/hr (2+2) he is earlier by 5 min

distance =(product of two speed /difference two speed )* difference in time arrival

distance =(2* 4 /2)* ( 6/60)

distance = 4/10 or 400m.