Question

Susheela is twice as old as her son. In four years she will be four times as old as her son was
9 years ago. How much old is each now?​

Answer 1

Step-by-step explanation:

Let age of Susheela=2x

So age of her son=x

AQ,

2x+4=4(x-9)

2x+4=4x-36

2x=40

x=20

Therefore, age of son=20 yrs

Age of Susheela= 20*2=40 yrs

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Answer 2

Step-by-step explanation:

Susheela is 40; her son is 20.

Let x=her son's age now.

Her age now is 2x; twice her son's age.

In four years, Susheela will be 2x + 4 (her present age plus 4 years).

Nine years ago her son was x - 9 (his present age minus 9).

Her age in 4 years (2x+4), will be equal to her son's age nine years ago (x-9) times four:

2x + 4 = 4(x -9)

2x + 4 = 4x - 36

2x + 4 [- 2x] = 4x - 36 [-2x]

4 = 2x - 36

4 [+36] = 2x - 36 [+36]

40 = 2x

20 = x (her son's age now)

2x = 40 (her age now, which is twice her son’s age now)