Math, asked by ammusamammu, 10 months ago

Susheela travelled (15m^2n+25mn^2+5mn) km in 5mn hours. Find the speed

Answers

Answered by RonakhRaj
0

Step-by-step explanation:

Distance travelled by Susheela,(15m²n+25mn²+5mn)km

Time taken= 5mn hours

Therefore, (15m²n+25mn²+5mn) ÷ 5mn

= 5mn×(3m+2n+1) ÷ 5mn [Taking common factor]

= 3m+2n+1 [Satisfying 5mn by 5mn=1]

Therefore, the Avg. speed is 3m+2n+1

Hope it helps!

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