Question

Sushil is now 4 times as old as Sunil. Five years ago Sushil was 7 times as old as Sunil was then .Find out the present age of both of them?

Answer 1

Answer:

Sunil's age =10 and sushil's age = 40

Step-by-step explanation:

let the age of sunil be x

sushil's age = 4x

4x-5=7 (x-5)

4x-5=7x-35

4x-7x= --35+5

-3x=-30

-x = -30/-3

-x=-10

X = 10

Sunil's age = 10

Sushil's age be 10*4=40

Answer 2

The present age of Sushil and Sunil is 40 and 10 respectively.

Given,

Sushil is now 4 times as old as Sunil. Five years ago Sushil was 7 times as old as Sunil was then.

To Find,

The present age of Sunil and Sushil.

Solution,

The method of finding the present age of Sunil and Sushil is as follows -

Let, the present age of Sunil be x.

According to the question, the present age of Sushil is 4x.

Since five years ago Sushil was 7 times as old as Sunil was then, we can write the following equation -

$4x-5=7 (x-5)$

⇒ $4x-5=7x-35$

⇒ $4x-7x= --35+5$

⇒ $-3x=-30$

⇒$x= \frac{-30}{-3} =10$

So, the present age of Sunil is 10.

So, the present age of Sushil is $4x=4*10=40$.

Hence, the present age of Sunil and Sushil is 10 and 40 respectively.

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