Question

sushil is now 4 times as old as sunil. five years ago sushil was 7 times as old as sunil was then. find the present age of each of them?

Answer 1

Let the age of Sunil be `x` yrs
Then the age of sushil = 4x years
five years ago sunil`s` age = (x - 5) years
And Sushil`s age five years ago = (4x - 5) years
But ti is given that five years ago the age of sushil is 7 times of sunil`s age
⇒7(x - 5) = 7x - 35
∴7x - 35 = 4x - 5
⇒7x - 4x = -5 + 35
⇒3x = 30
⇒x = 30/3
∴x = 10 years
Sunil`s age = x = 10 years
and Sushil`s age = 4x = 4* 10
=40 years.

Answer 2

Let Sunil age =  x
Sushil age = 4x

Five years ago

Sunil age  = x - 5
Sushil age = 4x - 5

Given that
4x - 5 = 7(x - 5)

4x - 5 = 7x - 35

3x = 30
 x= 10

Sunil age = 10
Sushil age = 40