Question

Sushila is now 4 times as old as sunil . Five years ago Sushil was 7 times as old as Sunil was then.find the present age of each of them

Answer 1

Let the age of Sunil be x years

So, the age of Sushila is 4x years

According to the question,

Five years ago Sushil was 7 times as old as Sunil was then

Thus, both ages 5 years ago

Sunil = (x-5) years

Sushila = (4x - 5) years

Now, ATQ

Equation will be

⇒ (4x - 5) = 7(x - 5)

⇒ 4x - 5 = 7x - 35

⇒ 35 - 5 = 7x - 4x

[By transporting (-35) to LHS and (4x) to RHS]

⇒ 30 = 3x

⇒ 30 ÷ 3 = x

[By transporting 3 to LHS]

⇒ 10 = x

Hence,

• Age of Sunil is = x years = 10 years
• And age of Sushila = 4x = 4*10 = 40 years

Answer 2

Answer:

Given :-

Sushila is now 4 times as old as sunil . Five years ago Sushil was 7 times as old as Sunil was then.

To Find :-

Present age

Solution :-

Present age of Sunil = x

Present age of Sushila = 4x

Five years ago

Age of sunil = x - 5

Age of Sushila = 4x - 5.

Now,

4x - 5 = 7(x - 5)

4x - 5 = 7x - 35

7x - 4x = 35 - 5

3x = 30

30/3 = x

10 = x

Now,

Present age of Sunil = 10 years

Present age of Sushila = 4(10) = 40 years