Susie begins a new walking program with 600 m on the first day. Each day, she will increase her walk by 200 m. How many kilometers will she walk on day 4 of her program?
Answers
Answer:
The following sum can be solved by a sequence concept .
For the following sum/problem it is given that , each day , he distance Susie walks will increase by 200 km . So it means that her walk is progressing and will be differ by 200km , so that is why we need to solve this by arithmetic sequence .
Formal to be used -:
aₙ = a₁ + (n - 1) (d)
where aₙ is the nth term, a₁ is the first term, and d is the common difference
→a₁ = 600 m (distance in the beginning)
→n = 4(because we are solving for the distance for the 4th day)
→d = 200 m
aₙ = a₁ + (n - 1) (d)
a₁₈ = 600 m + (4-1)(200 m)
a₁₈ = m = 1.2km( in meter 1200 m)
(☘Apologies for any mistakes in the above answer)
(☘not a copied answer)
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Answer:
Susie will walk 1.2 kilometers on the day 4 of the walk program.
Explanation:
Given :
Susie begins a new walking program
She walks on first day = 600 m
She will increase her walk by 200 m each day.
To Find:
How many kilometers will she walk in day 4 of the program
Solution :
Since we are given that on he first day of the program Susie walks 600 m
After it she will increase 200 m each day
then her walk on the day 2 of the program = 600 + 200 = 800 m
her walk on the day 3 of the program = day 2 walk + 200
= 800 m + 200 m = 1000 m
her walk on the day 4 of the program = walk on day 3 + 200 m
= 1000m + 200 m = 1200 m
Since we know that 1 km = 1000 m
so 1200 m = 1200/1000 = 1.2 kilometers
Hence we have calculated that Susie will walk 1.2 kilometers on the day 4 of the walk.
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