suvidya borrowed a sum of 3000 rupees at 8 p.c.p.a.interest for a year from her bank to buy a computer of 2400 rupees over and above what had she borrowed
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P = ₹3000
R = 8%p.a.
T = 1year
S.I. = P×R×T ÷ 100
= 3000×8×1 ÷ 100
= ₹240
= ₹240 A = P + SI
= ₹240 A = P + SI A = 3000 + 240
= ₹240 A = P + SI A = 3000 + 240A = ₹3240
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