Math, asked by godclutch568, 5 months ago

Suvidya borrowed a sum of 30000 rupees at 8 p.c.p.a. interest for a year from her
bank to buy a computer. At the end of the period, she had to pay back an amount of 2400
rupees over and above what she had borrowed.​

Answers

Answered by lovely2012gmailcom
21

Step-by-step explanation:

principal=₹30000

rate of interest =8

interest =2400

time=1

the total amount returned to the bank =30000+2400=32400

Answered by Anonymous
8

Complete question is as follows -

Suvidya borrowed a sum of Rs 30000 at 8 p.c.p.a. interest for a year from her bank to buy a computer. At the end of the period, she had to pay back an amount of Rs 2400 over and above what she had borrowed. Based on this information fill in the blanks below.

1. Principal = Rs__

2. Rate of interest =__%

3. Interest = Rs__

4. Time =__year.

5. The total amount returned to the bank = 30,000 + 2,400 = Rs__

Given - Principal, rate, time and interest

Find - Solution of blanks

Solution -

1. Principal amount is Rupees 30,000

2. Rate of interest is 8%

3. Interest is Rupees 2400

4. Time is one year

5. Total amount to be returned to bank is Rupees 32,400.

The related formula for calculation, when any varible is absent, is S.I. = PRT/100. In this formula, S.I. is simple interest, P is principal, t is time and r is rate of interest.

Further, Amount = Principal + Interest.

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