Question

Suyash scored 10 marks more in second test than that in the first. 5 times the score of the second test is the same as square of the score in the first test. Find his score in the first test. Solve the word problem

Answer 1

SOLUTION:
Let Suyash scored marks in 1st test = x
Marks scored by Suyash in 2nd test = x+10

ATQ
5(x + 10) = x²
5x +50 = x²
x² - 5x - 50 = 0
x² - 10x + 5x - 50
[ By middle term splitting]
x(x - 10 ) + 5( x - 10) = 0
( x + 5)(x - 10) = 0
x +5= 0 or x -10= 0
x = -5 or x = 10
Marks Can't be negative (x = -5).

Hence, Suyash score in the first test = 10 marks.

HOPE THIS WILL HELP YOU...

Answer 2

let the score of the suyash in first test be x.
So, in second test score be (x + 10).

now in question given,
5 times the score of the second test is the same as square of the score in the first test

so, 5(x + 10) = x²

5x + 50 = x²

X² - 5x - 50 = 0

X² - 10x + 5x - 50 = 0

X(x - 10) + 5(x + 10) = 0

(X + 5)(x - 10) = 0

x = 10 , x = -5
here's x have to values , we know score in test can't be negative
Hence x ≠ -5

∴ x = 10
hence, the score of suyash in first exam is 10.