Suzie is going on a hike and arrives at the top of a cliff. While standing on a cliff, Susie tosses a .21 kg rock into the valley below. If she throws the rock horizontally with a speed of 3.5 m/s and it hits the ground 8.3 meters from the base of the cliff. What height was the rock tossed from?
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Given info : Suzie throws the rock horizontally with a speed of 3.5 m/s and it hits the ground 8.3 m from the base of cliff.
To find : what the height was the rock tossed from ?
solution : it is based on horizontal projectile motion.
we know, path followed by particle thrown in horizontal direction is y = gx²/2u²
where u is initial horizontal speed of particle.
g is acceleration due to gravity
and x is horizontal distance covered by particle and y is vertical distance covered by it.
here u = 3.5 m/s , g = 10 m/s², x = 8.3 m
so, y = (10 × 8.3²)/(2 × 3.5²)
= 28.118 ≈ 28.12 m
Therefore the rock was tossed from 28.12m
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