Question

swami packed 288 oranges and 624 apples in boxes. He packed oranges and apples in separate boxes. If he put equal number of fruit each box, find the maximum number of of fruits he put in each box.

Answer 1

Answer :

To get the desired answer we will find the H.C.F of these two numbers.

Total number of Oranges = 624

Total number of apples = 288

Now,

$\textbf{H.C.F. of 288 and 624 by}$$\textbf{prime factorization method.}$

On prime factorising we get,

288 = 2×2×2×2×2×3×3

and

624 = 2×2×2×2×3×13

Their HCF = 2×2×2×2×3 = 48

Thus, we find that to put the equal number of friuts in each box we have to put 48 fruits in each box.

Answer 2

Answer:

Step-by-step explanation:

ANSWER IS :- To get the desired answer we will find the H.C.F of these two numbers.

Total number of Oranges = 624

Total number of apples = 288

Now,

On prime factorising we get,

288 = 2×2×2×2×2×3×3

and

624 = 2×2×2×2×3×13

Their H.C.F. = 2×2×2×2×3 = 48

Thus, we find that to put the equal number of fruits in each box we have to put 48 fruits in each box.