Question

swapna is 25 years older than her daughter suma 6 years later swpna will be thrice as old as suma find their present ages​

Answer 1

Swaapna be x

Suma be y

X=y+25

X+6=( y+6)3

X+6=3y+18

Y+25+6=3y+18

2y =31-18

Y =6.5

Swapma =31.5 yrs

Suma =6.5yrs

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Answer 2

Answer :

• Present age of suma is 18.5
• Present age of swapna is 43.5

Given :

• swapna is 25 years years older than her daughter

• Let the age of suma be x
• Let the age of swapna be x + 25

After 6 years :

• Let the Age of suma be x - 6
• Let the Age of swapna = (x + 25) - 6 = x + 25 - 6 = x + 19

Given,

6 years later swpna will be thrice as old as suma so,

• (x + 19) = 3(x - 6)

↬ (x + 19) = 3(x - 6)

↬ x + 19 = 3x - 18

↬ x - 3x = -18 - 19

↬ -2x = -37

↬ 2x = 37

↬ x = 37/2

↬ x = 18.5

Finding the present ages :

↬ Present age of suma = x = 18.5

↬ Present ages of swapna = x + 25 = 18.5 + 25 = 43.5

Hence,

• Present age of suma is 18.5
• Present age of swapna is 43.5

Verification :

↬ x + 19 = 3(x - 6)

↬ 18.5 + 19 = 3(18.5 - 6)

↬ 37.5 = 55.5 - 18

↬ 37.5 = 37.5

Hence , Verified