Question

Swaraj Express Departs From New Delhi With The initial Velocity Of 24m/s , In 45 Seconds , Find The Acceleration Of Swaraj Express
.

Answer 1

Acceleration : V-U/T

                       : 0-24/45

                     : 0.5333 ms^-2 answer hai

Answer 2

Answer:acc. = v-u/t

U=24

V=0

T=45

0-24/45

-24/45

-1.875

Step-by-step explanation: