Swaraj Express Departs From New Delhi With The initial Velocity Of 24m/s , In 45 Seconds , Find The Acceleration Of Swaraj Express
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Acceleration - v-u/t
= 0-24/45
answer will be = 0.5333 ms^-2
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Hey... ✌️
Acceleration : V-U/T
: 0-24/45
: 0.5333 ms^-2
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