Math, asked by abinashacharya36, 9 months ago

Swati, when get married to jayanta her age, was 3/4 th of her husband's age. After 12 years her
age became 5/6 th of her husband's age. Then what's the age of Swati when she got married??​

Answers

Answered by abhi569
3

Answer:

18 year

Step-by-step explanation:

Let the age of her husband be 4a, when she got married, her age 3/4 of 4a.

So, when she got married:

Her age = 3a

Husband's age = 4a

After 12 years:

Her age = 3a + 12

Her husband's age = 4a + 12

In question, that time she is 5/6 of her husband's age.

= > her age = 5/6 of her husband's age

= > 3a + 12 = (5/6) (4a + 12)

= > 6(3a + 12) = 5(4a + 12)

= > 18a + 72 = 20a + 60

= > 72 - 60 = 20a - 18a

= > 12 = 2a

= > 6 = a

Hence, age of swati when she got married was:

3a = 3(6) = 18 year

Answered by parshanaboinab74
0

Answer:

18

Step-by-step explanation:

her age 3a---->eq'n (1)

her hubby age 4a

3a+12=(5/6)(4a+12)

6(3a+12)=5(4a+12)

18a+72=20a+60

72-60=20a-18a

12=2a

a=6---->substitude in eq'n(1)

3(6)==18

Ans: 18 years

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