Sweater can do a piece of work in 20 days and Radhika does the same work in 25 days they both work together for 10 days and then sweater go away in how many days will finish the remaining work
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Answer:
A's 1 day's work =
25
1
Similarly, B's 1 day's work =
20
1
A's and B's together 1 day's work
25
1
+
20
1
=
100
4
+
100
5
=
100
4+5
=
100
9
Their 5 day's work together = 5 x 1 day's work
1−
100
45
=
100
100
−
100
45
=
100
100−45
=
100
55
Now, this remaining work is done by B.
Let B takes x days to complete it.
20
1
×x=
100
55
⇒x=
100
55
×20
⇒x=
5
55
⇒x=11
Hence, B will finish the remaining work in 11 days.
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