Question

sweety runs around a square park of side 75 metre. bulbul runs around a rectangular park of length 175 metre and breadth 125 metre . who covers less distance​

Answer 1

Given:

• Sweety runs around a square park of side =75 metre.

• Nikhil runs around a rectangular park of length =175m

•Breadth =125meter

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To Find :

• Who covers Less distance =?

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Solution :

In case of Sweety

$\\ \implies \sf \: side \: of \: square \: park = a = 75m \\ \\ \\ \implies \sf \: perimeter = 4a = 4 \times 75 \\ \\ \implies \boxed{\sf {\: perimeter = 300metre}}$

•Distance covered by sweety=300m

In case of Bulbul,

$\bullet \bf \: length = l = 60m \\ \\ \bullet \bf \: breadth = b = 45m$

$\implies \sf \: perimeter = 2(l + b) \\ \\ \implies \sf \: perimeter = 2(60 + 45) \\ \\ \implies \sf \: perimeter \: = 2(105) \\ \\ \: \implies \boxed{\sf{ perimeter = 210m}}$

•Distance covered by bulbul is 210m

Therefore, Bulbul covers less distance.

Answer 2

Step-by-step explanation:

if didn't understand my handwriting I am writing in below

$sweety \: runs \: around \: a \: square \: park \: of \: side = 75m \\ the \: perimeter = 4 \times sides \\ = 4 \times 75 \\ = 300m \: \\ \\ \\ bulbul \: runs \: around \: rectangular \: park \: length = 175 \\ the \: breadth = 125 \\ = 2 \times (l + b) \\ = 2 \times (175 +125) \\ = 2 \times 300 \\ = 600 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ so \: sweety \: covers \: less \: distance \:$

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