Math, asked by Sumityadav9167, 11 months ago

Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ?
A) 18 years
B) 21 years
C) 23 years
D) 17 years

Answers

Answered by Anonymous
2
At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x
12 years after:
Age of Sudeer = 4x+12
Age of Swetha = 3x+12
Now the equation is 3x+12=5/6(4x+12)
Solving equation we get x=6
Hence Swetha got married at the age of 18.
Answered by Anonymous
0
Q:

Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ?

A) 18 years
B) 21 years
C) 23 years
D) 17 years

Answer:   A) 18 years 

Explanation:

At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x

12 years after:

Age of Sudeer = 4x+12

Age of Swetha = 3x+12

Now the equation is 3x+12=5/6(4x+12)

Solving equation we get x=6

So, Swetha got married at the age of 18.
Similar questions