Swimming Pools in club A and club B contain 500 and 200 liters of water,
respectively. Water is pumped out of swimming pool A at the rate of Q
liters per minute and water is being added to swimming pool B at the rate
of G liters per minute. , How many hours will elapse before the two tanks
contain equal amounts of water?
Answers
Answered by
13
Given:
Water in swimming pool of club A = 500 litres
Water in swimming pool of club B = 200 litres
Rate at which water is pumped out from A = Q litres/min
Rate at which water is pumped out from B = G litres/min
To find:
Number of hours at which volume of both the pools become equal.
Solution:
Let 't' be the number minutes taken so that the volume of the two pools become equal.
Volume taken out from pool A after 't' minutes:
So, volume left in pool A after 't' minutes = 500-
Volume put to pool B after 't' minutes:
So, volume of pool B after 't' minutes = 200 +
Now, let us put both the volumes equal:
So, after the volume of the two pools will be equal.
Similar questions