Question

∆ SWT ~ ∆ABH , 12 × ∆ ABH = 18 × SWT IF BH=32 , THEN FIND WT?​

Answer 1

ΔABC ∼ ΔDEF

ΔABC ∼ ΔDEF⇒ AB/DE = Perimeter of ΔABC/Perimeter of ΔDEF

ΔABC ∼ ΔDEF⇒ AB/DE = Perimeter of ΔABC/Perimeter of ΔDEF⇒ AB/9 = 64/48

ΔABC ∼ ΔDEF⇒ AB/DE = Perimeter of ΔABC/Perimeter of ΔDEF⇒ AB/9 = 64/48⇒ AB = 64/48 × 9

ΔABC ∼ ΔDEF⇒ AB/DE = Perimeter of ΔABC/Perimeter of ΔDEF⇒ AB/9 = 64/48⇒ AB = 64/48 × 9∴ AB = 12 cm