Sxample 47 Calculate a) the actual volume of one molecule of water. b) the radius of a water molecule assuming to be spherical (density of water = 1 g ml-2).
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Explanation:
Density of water (ρ) = 1g/cm^2
Molar mass of water (M) = 18 g/mol
∴ Molar volume (Vm) = M/ρ
Vm = 18 cm3/mol
∴ Volume of 1 molecule of water = Vm/NA
Where NA is Avogadro number
Volume of 1 molecule of water = 18/(6.022 × 10^23)
Volume of 1 molecule of water = 2.989 × 10^-23 ≈ 3 × 10^-23.
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