Question

Syama age is 3 times the age of her son Ankit 10 years ago Syama was 5 times the age of Ankit find the present ages​

Answer 1

Syama = 60 Years

Ankit = 20 Years

Step-by-step explanation:

Given:

• Syama is 3 times of age of Ankit.
• 10 years ago she was 5 times the age of Ankit.

To Find:

• What are their present ages ?

Solution: Let the present age of Ankit be x years. Therefore,

Present age Syama = 3 times of x

∴ Syama's age = 3x years.

[ 10 years ago their ages were ]

• Ankit's age = (x – 10) years
• Syama's age = (3x – 10) years

A/q

• 10 years ago she was 5 times the age of Ankit.

$\implies{\rm }$ (3x – 10) = 5(x – 10)

$\implies{\rm }$ 3x – 10 = 5x – 50

$\implies{\rm }$ – 10 + 50 = 5x – 3x

$\implies{\rm }$ 40 = 2x

$\implies{\rm }$ 40/2 = x

$\implies{\rm }$ 20 = x

So, their present ages are

➢ Ankit age is x = 20 years

➢ Syama age is 3(20) = 60 years.

Answer 2

Answer:

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