Math, asked by eatergloo, 6 months ago

syeem age mohans age was twice of sohan . if the sum of their present age is 40 years.
find the rato of their ages
.

Answers

Answered by prasantsantos
1

Answer:

1:2

Step-by-step explanation:

Let age of Sohan be x and that of Mohan be y

    Mohans age is twice of Sohan   : y=2x

Thus the Ratio of their ages is 1:2

    Sum of their present age is 40 years  : x + y =40    

                       x + y =40    

                       x + 2x =40

                           3x=40

                             x=40/3

Sohan is 40/3 [13.333] yrs old and Mohan is 80/3[26.666] yrs old.

Given x + y = 40. Lets check whether its true or not.

         \frac{40}{3}  + \frac{80}{3} = \frac{120}{3} = 40

Answered by kumbharemayank30
1

Answer:

Let 'x' be the age of sohan.

and sayeem's and mohan's age be 2x.

now,

sum of their ages =40------------------ (given)

 sayeem's age + mohan's age + sohan's age = 40

Therefore, the equation will be as follows :

        2x + 2x + x =40

                      5x = 40

                        x =8

sayeem's age = 2x = 2*8 = 16

mohan's age = 2x = 2*8 = 16

sohan's age = x = 8

Therefore, the ratio will be as follows

8 : 16 : 16

That's all.

Step-by-step explanation:

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