Question

symmetric form of the line through (-2,0) having slope '-1/root 3' is

Answer 1

we have to find the symmetric form of the line through (-2,0) having slope -1/√3.

solution : Symmetric form of line is represented by x/a + y/b = 1, where a is x - intercept and b is y - intercept and a ≠ 0 , b ≠ 0.

first find the equation of line using (y - y₁) = m(x - x₁) where m is slope of line and (x₁ , y₁) is a point on the line.

here (x₁ , y₁) = (-2,0) and m = -1/√3

so, (y - 0) = -1/√3(x + 2)

⇒√3y + x + 2 = 0

⇒x + √3y = -2

⇒x/-2 + √3y/-2 = 1

⇒x/(-2) + y/(-2/√3) = 1

Therefore symmetric form of the line is x/(-2) + y/(-2/√3) = 1.

Answer 2

Answer:

we have to find the symmetric form of the line through (-2,0) having slope -1/√3.

Step-by-step explanation:

solution : Symmetric form of line is represented by x/a + y/b = 1, where a is x - intercept and b is y - intercept and a ≠ 0 , b ≠ 0.

first find the equation of line using (y - y₁) = m(x - x₁) where m is slope of line and (x₁ , y₁) is a point on the line.

here (x₁ , y₁) = (-2,0) and m = -1/√3

so, (y - 0) = -1/√3(x + 2)

⇒√3y + x + 2 = 0

⇒x + √3y = -2

⇒x/-2 + √3y/-2 = 1

⇒x/(-2) + y/(-2/√3) = 1

Therefore symmetric form of the line is x/(-2) + y/(-2/√3) = 1.