Question

system.
Ex. 4.4.1 A cricket ball of mass 100 g moving
with velocity of 20 m/s is brought to rest by a
player in 0.05s. Find the impulse of the force
and the average force applied by the player.​

Answer 1

m=100g

m=0.1kg

Impulse =ΔP

=|P2-P1|

=|0-(0.1×20)|

Impulse=2kgm/s

FΔt=I

F=I/Δt

F=2kgm/s/0.05s

F=40kgm/s^2

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Answer 2

Answer:

Impulse = Mass × Change in velocity

= 100 × 10^-3 kg × (0 - 20) m/s

= -2 kgm/s

Force = Impulse / Time

= -2 kgm/s / (0.05 s)

= -40 N

[Note: Negative sign indictes that Force and impulse are in the direction opposite to the motion of cricket ball]

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