Computer Science, asked by LakshmishreeR, 9 months ago

System.out.println(Math.rint(-9.4)+Math.sqrt(9.0); With explanation​

Answers

Answered by 9368082539sre
4

The answer is -6.0 because math.rint Will return -9.0 and math.sqrt will return 3.0 and it will be in double type

Answered by Qwdubai
0

System.out.println(Math.rint(-9.4)+Math.sqrt(9.0); Output: -6

The above code is from the Java language.

Math.rint() method of Java rounds off the value in the argument to the nearest integer.

Syntax: Math.rint(argument);

Example: Math.rint(23.75);

Output: 24

In the given code, -9.4 is a floating-point value.

Math.rint(-9.4) will return -9.0.

Math.sqrt() method of Java returns the square root of the value entered in the argument.

Syntax: Math.sqrt(argument);

Example: Math.sqrt(25.0);

Output: 5.0

In the given code, 9.0 is a double value.

Math.sqrt(9.0) will return the square root of 9.0. 3.0 is the square root of 9.0.

Now, Math.rint(-9.4)+Math.sqrt(9.0) will add the values of Math.rint(-9.4) and Math.sqrt(9.0).

-9.0 + 3.0 = -6.0

System.out.println() prints the argument passed inside it in the new line.

Therefore, the output of the following code is -6.0.

#SPJ3

Similar questions