Question

system.Out.Println("max of" + a + and + b + "is" +max); are find arrer

Answer 1

$\huge \bold{ERROR}$

Any obstruction or mistake in the coding that stops the execution of the program is an error.

$\huge \bold{TYPES \: OF \:ERROR}$

◼$\bold{Syntax \: error}$

The errors caused due to any gramitical mistake done by user while writing coding of the program are called syntax error.

Example :- Missing of semicolon or double qoutes.

◼$\bold{Logical \: error}$

The error present in the logic of program, are known as logical errors.

Example :- If the user want to print even number and he did logic

for(i=1 ; i<=10 ;i+=2)

System. out. println(i);

It will print all odd numbers from 1 -10 ,while user wants even numbers.

So, coding should be,

for(i=0 ; i<=10 ;i+=2)

System. out. println(i);

◼$\bold{Run \: time\: error}$

After the syntax error and logic error are removed , there are errors that appears during execution of program they are known as run time error.

Example :- Dividing a number by zero will give an infinite value.

$\bold{IN \: THE \: QUESTION }$

sys tem . Out . Println("max of" +a+ and + b+"is" +max);

In the following segment of program ,there is $\bold{SYNTAX \: ERROR}$

Because,

▶sys tem . out . println should be written as $\bold{System \: . \: out\: . \: println}$

▶The text written in brackets should be

$\bold{"max \: of" +a+"and" +b+"is"+max}$

So, the coding should be,

$\boxed{\bold{System \: . \: out\: . \: println("max \: of" +a+"and" +b+"is"+max)}}$

Answer 2

Answer:

\huge \bold{ERROR}ERROR

Any obstruction or mistake in the coding that stops the execution of the program is an error.

\huge \bold{TYPES \: OF \:ERROR}TYPESOFERROR

◼\bold{Syntax \: error}Syntaxerror

The errors caused due to any gramitical mistake done by user while writing coding of the program are called syntax error.

Example :- Missing of semicolon or double qoutes.

◼\bold{Logical \: error}Logicalerror

The error present in the logic of program, are known as logical errors.

Example :- If the user want to print even number and he did logic

for(i=1 ; i<=10 ;i+=2)

System. out. println(i);

It will print all odd numbers from 1 -10 ,while user wants even numbers.

So, coding should be,

for(i=0 ; i<=10 ;i+=2)

System. out. println(i);

◼\bold{Run \: time\: error}Runtimeerror

After the syntax error and logic error are removed , there are errors that appears during execution of program they are known as run time error.

Example :- Dividing a number by zero will give an infinite value.

\bold{IN \: THE \: QUESTION }INTHEQUESTION

sys tem . Out . Println("max of" +a+ and + b+"is" +max);

In the following segment of program ,there is \bold{SYNTAX \: ERROR}SYNTAXERROR

Bcoz. ,

▶sys tem . out . println should be written as \bold{System \: . \: out\: . \: println}System.out.println

▶The text written in brackets should be

\bold{"max \: of" +a+"and" +b+"is"+max}"maxof"+a+"and"+b+"is"+max

So, the coding should be,

\boxed{\bold{System \: . \: out\: . \: println("max \: of" +a+"and" +b+"is"+max)}}

System.out.println("maxof"+a+"and"+b+"is"+max)

Step-by-step explanation:

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