Question

system shown in figure is in equilibrium.The magnitude of change in tension in the string just before and just after, when one of the spring is cut. Mass of both the blocks is same and equal to m and spring constant of both spring is k .( neglect any effect of rotation )
1).mg/2
2).mg/4
3).3mg/4
4).3mg/2

GIVE PROPER ANSWER WITH BRIEF EXPLANATION..

(irrelevant will be reported)
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Answer 1

Answer:

Option 3 is seems as Right Answer .

Explanation:

hope this help.

Answer 2

Ti = mg

2kx = 2mg

∴ kx = mg

One kx force (acting in upward direction) is suddenly removed. So net downward force on system will be kx or mg. Therefore net downward acceleration of system,

a = mg/2m

= g/2

Free body diagram of lower block gives the equation.

mg−Tf = ma = mg/2

Tf = mg/2

From these two equations we get,

∆T = mg/2

I HOPE YOU SATISFIED WITH MY ANSWE.

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