Question

t^2+0.2t-4=0. Let's see if you can solve this. no spam otherwise will be reported​

Answer 1

Answer:

t = 1.9 or (-2.1)

Step-by-step explanation:

We are given,

t² + 0.2t - 4 = 0

at² + bt + c = 0

where a = 1, b = 0.2, c = -4

Using the Quadratic formula,

t = (-b ± √(b² - 4ac))/2a

t = (-(0.2) ± √((0.2²) - 4(1)(-4)))/2(1)

t = (-0.2 ± √0.04 + 16)/2

t = (-0.2 ± √16.04)/2

t = (-0.2 ± 4.00(approx.))/2

t = (-0.2 + 4)/2 or (-0.2 - 4)

t = 3.8/2 or (-4.2)/2

∴ t = 1.9 or (-2.1)

Hope it helped and believing you understood it........All the best