Question

t^2-15 find the zeros of the quadratic polynomials and verify the relationship between the zeros of the coefficient ​

Answer 1

Step-by-step explanation:

Given -

• p(t) = t² - 15

To Find -

• Zeroes of the polynomial and verify the relationship between the zeroes and the coefficient .

Now,

→ t² - 15

→ (t)² - (√15)²

It is in the form of

• a² - b² = (a + b)(a - b)

→ (t + √15)(t - √15)

Zeroes are -

→ t + √15 = 0 and t - √15 = 0

→ t = -√15 and t = √15

Verification :-

As we know that :-

• α + β = -b/a

→ -√15 + √15 = -(0)/1

→ 0 = 0

LHS = RHS

And

• αβ = c/a

→ -√15 × √15 = -15/1

→ -15 = -15

LHS = RHS

Hence,

Verified...