Question

t^2-15
sum of zeroes
and
product of zeroes​

Answer 1

Step-by-step explanation:

Given -

• p(t) = t² - 15

To Find -

1. Sum of zeroes
2. Product of zeroes

Now,

→ t² - 15

→ (t)² - (√15)²

Using the identity of a² - b² = (a + b)(a - b), we get :

→ (t + √15)(t - √15)

Zeroes are -

→ t + √15 = 0 and t - √15 = 0

→ t = -√15 and t = √15

Then,

Sum of zeroes :-

→ -√15 + √15

→ 0

And

Product of zeroes :-

→ -√15 × √15

→ -15