Question

t^2-23t+22. Factorise them.​

Answer 1

Answer:

Hey frnd...

Here is ur ans...

Step-by-step explanation:

${t}^{2} - 23t + 22 = 0 \\ {t}^{2} - 22t - 1t + 22 = 0 \\ t(t - 22) - 1(t - 22) = 0 \\ (t - 22)(t - 1) = 0 \\ t = 22 \: or \: 1$

Hope this helps u...

Answer 2

Answer:

..

Step-by-step explanation:

t^2-t-22t+22

=t(t-1)-22(t-1)

=(t-1)(t-22)