Question

t^2 -2t -8=0

How do i split it, to get t=4 and t= -2​

Answer 1

t² - 2t - 8 = 0

» t² - 4t + 2t - 8 = 0

» t(t-4) + 2(t-4) = 0

» (t+2)(t-4) = 0

» t = 4, -2

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• Find the roots of the quadratic equation.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

${t}^{2} - 2t - 8 = 0$

$\implies {t}^{2} - 4t + 2t - 8 = 0$

$\implies t(t - 4) + 2(t - 4) = 0$

$\implies (t + 2)(t - 4) = 0$

Therefore, Either $(t+2)=0$ or $(t-4)=0$.

So,

$t + 2 = 0$

$\implies t = - 2$

Also,

$t - 4 = 0$

$\implies t = 4$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• The roots of the given Quadratic equation are -2 and 4.