Question

T 2/3 of first order reaction chemical reaction is 6.93 minutes

Answer 1

Answer:

$K= \large\frac{0.693}{t_{Y2}}$

$\quad= \large\frac{0.693}{6.93}$

$\quad= minute^{-1}$

$K= \large\frac{2.303}{t} $$ \log \large\frac{100}{100-99}$

[if $a= 100, x=99\;and a-x=1]$

$\therefore \large\frac{0.693}{6.93}= \frac{2.303}{t} $$\log \large\frac{100}{1}$

$t= 46.06\;minute$

Explanation: