Question

t^2-3t-2=0 then t= ​

Answer 1

SOLUTION

$= > {t}^{2} - 3t - 2 = 0 \\ \\ = > t(t - 3) - 2(t - 3) = 0 \\ \\ = > (t - 3) \: (t - 2) = 0 \\ \\ = > t - 3 = 0 \: \: \: \: \: or \: \: \: \: t -2 = 0 \\ \\ = > t = 3 \: \: \: \: or \: \: \: t = 2$

hope it helps ☺️

Answer 2

Answer:-

$\bold{{t}^{2} - 3t - 2 = 0}$

[Factorize]

$\bold{t(t - 3) - 2(t - 3) = 0}$

$\bold{(t - 3)(t - 2) = 0}$

$\bold{t - 3 = 0 \: \ ,\: \: \: t - 2 = 0}$

$\bold{t = 3 \: \:, \: t = 2}$

Therefore value of t=3 , 2