Math, asked by shivi4820, 11 months ago

t^2 +3t-4=0 find the value of t​

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Answered by brunoconti
2

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Answered by prashant8219
0

Step-by-step explanation:

t^2+3t-4=0

t^2 -t+4t-4=0

t(t-1)+1(t-1)=0

t-1=0 or t+1=0

t=1 or t=-1

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