Question

t^2-8t-18=0 find th value of t

Answer 1

Hello,

Using completing square method,

t^2-8t-18


(t)^2-2.t.4+(4)^2-(4)^2-18=0

here,

(a-b)^2 (use)

(t-4)^2=(4)^2+18

(t-4)^2=16+18

(t-4)^2=34

(t-4)=Root 34

t=4+root34


or,

t=4-root34


Quardratic equation has two roots.


thanks