(t + 2) (t + 4) =what is the answer
Answers
Answer:
t² + 6t + 8
Step-by-step explanation:
t(t+4) + 2(t+4)
= t² + 4t + 2t + 8
= t² + 6t + 8 [answer]
Step-by-step explanation:
Formula Used :
\begin{gathered}\large{\color{cyan}{\bigstar}} \: \: {\underline{\boxed{\red{\sf{ Gravitational \: Field \: = \dfrac{Weight}{Mass}}}}}} \\ \\ \end{gathered}
★
GravitationalField=
Mass
Weight
⚝ Let the Weights :
➙ {\sf{ W_1 = Weight \: of \: first \: Object }}W
1
=WeightoffirstObject
➙ {\sf{ W_2 = Weight \: of \: second \: Object }}W
2
=WeightofsecondObject
➙ {\sf{ W_3 = Weight \: of \: third \: Object }}W
3
=WeightofthirdObject
➙ {\sf{ W_4 = Weight \: of \: fourth \: Object }}W
4
=WeightoffourthObject
\qquad{\rule{150pt}{1pt}}
⚝ Calculating the Weights :
\begin{gathered} \\ \\ \end{gathered}
Weight of 1st Object :
\begin{gathered}{:\implies{\qquad{\sf{ Gravitational \: Field \: = \dfrac{Weight}{Mass}}}}} \\ \\ \ {:\implies{\qquad{\sf{ 15 = \dfrac{W_1}{10}}}}} \\ \\ \ {:\implies{\qquad{\sf{ W_1 = 15 \times 10 }}}} \\ \\ \ {\qquad{\textsf{ Weight of 1st Object = {\pink{\sf{150 \: N}}}}}}\end{gathered}
:⟹GravitationalField=
Mass
Weight
:⟹15=
10
W
1
:⟹W
1
=15×10
Weight of 1st Object = 150 N
\begin{gathered} \\ \\ \end{gathered}
Weight of 2nd Object :
\begin{gathered}{:\implies{\qquad{\sf{ Gravitational \: Field \: = \dfrac{Weight}{Mass}}}}} \\ \\ \ {:\implies{\qquad{\sf{ 13 = \dfrac{W_2}{15}}}}} \\ \\ \ {:\implies{\qquad{\sf{ W_2 = 13 \times 15 }}}} \\ \\ \ {\qquad{\textsf{ Weight of 2nd Object = {\purple{\sf{195 \: N}}}}}}\end{gathered}
:⟹GravitationalField=
Mass
Weight
:⟹13=
15
W
2
:⟹W
2
=13×15
Weight of 2nd Object = 195 N
\begin{gathered} \\ \\ \end{gathered}
Weight of 3rd Object :
\begin{gathered}{:\implies{\qquad{\sf{ Gravitational \: Field \: = \dfrac{Weight}{Mass}}}}} \\ \\ \ {:\implies{\qquad{\sf{ 9 = \dfrac{W_3}{20}}}}} \\ \\ \ {:\implies{\qquad{\sf{ W_3 = 9 \times 20 }}}} \\ \\ \ {\qquad{\textsf{ Weight of 3rd Object = {\pink{\sf{180 \: N}}}}}}\end{gathered}
:⟹GravitationalField=
Mass
Weight
:⟹9=
20
W
3
:⟹W
3
=9×20
Weight of 3rd Object = 180 N
\begin{gathered} \\ \\ \end{gathered}
Weight of 4th Object :
\begin{gathered}{:\implies{\qquad{\sf{ Gravitational \: Field \: = \dfrac{Weight}{Mass}}}}} \\ \\ \ {:\implies{\qquad{\sf{ 3 = \dfrac{W_4}{50}}}}} \\ \\ \ {:\implies{\qquad{\sf{ W_4 = 3 \times 50 }}}} \\ \\ \ {\qquad{\textsf{ Weight of 4th Object = {\purple{\sf{150 \: N}}}}}}\end{gathered}
:⟹GravitationalField=
Mass
Weight
:⟹3=
50
W
4
:⟹W
4
=3×50
Weight of 4th Object = 150 N
\qquad{\rule{150pt}{1pt}}
⚝ Comparing the Weight :
\begin{gathered}\qquad \: {\sf{ W_1 = 150 \: N}} \\ \end{gathered}
W
1
=150N
\begin{gathered}\qquad \: {\sf{ W_2 = 195 \: N}} \\ \end{gathered}
W
2
=195N
\begin{gathered}\qquad \:{\sf{ W_3 = 180 \: N}} \\ \end{gathered}
W
3
=180N
\begin{gathered}\qquad \:{\sf{ W_4 = 150 \: N}} \\ \\ \end{gathered}
W
4
=150N
Greatest : 195 N
\qquad{\rule{150pt}{1pt}}
⚝ Therefore :
❝ 2nd Object has the greatest weight (i.e, 195 N) . ❞