t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4) solve it
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LHS→t-2t-5-5+10t
=9t-10 →(1)
RHS→6+8t-3t+12
=5t+18→(2)
equating (1) and (2)
→9t-10=5t+18
→9t-5t=18+10
→4t=28
→t=28/4=7
Hence the Solution is t=7.
Hope it Helps...
Regards,
Leukonov.
=9t-10 →(1)
RHS→6+8t-3t+12
=5t+18→(2)
equating (1) and (2)
→9t-10=5t+18
→9t-5t=18+10
→4t=28
→t=28/4=7
Hence the Solution is t=7.
Hope it Helps...
Regards,
Leukonov.
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