(t+3)²-(t-3)² equals
a)2t²+18
b)-12t
c)12t
d)18
with solution
Answers
Answered by
5
By identity a²-b²=(a-b)(a+b)
(t+3)²-(t-3)²=(t+3+t-3)(t+3-t+3)
=(2t)(6)
=12t
so option (c) is correct
pls mark as brainliest
Answered by
5
Step-by-step explanation:
t² +9 + 6t - ( t² +9 -6t )
t² +9 +6t -t² -9 +6t
= 12t .........
right answer....okkkkkkk
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